Optimal. Leaf size=90 \[ -\frac{\cot ^2(c+d x)}{a d}+\frac{3 i \cot (c+d x)}{2 a d}-\frac{2 \log (\sin (c+d x))}{a d}+\frac{\cot ^2(c+d x)}{2 d (a+i a \tan (c+d x))}+\frac{3 i x}{2 a} \]
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Rubi [A] time = 0.121196, antiderivative size = 90, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.167, Rules used = {3552, 3529, 3531, 3475} \[ -\frac{\cot ^2(c+d x)}{a d}+\frac{3 i \cot (c+d x)}{2 a d}-\frac{2 \log (\sin (c+d x))}{a d}+\frac{\cot ^2(c+d x)}{2 d (a+i a \tan (c+d x))}+\frac{3 i x}{2 a} \]
Antiderivative was successfully verified.
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Rule 3552
Rule 3529
Rule 3531
Rule 3475
Rubi steps
\begin{align*} \int \frac{\cot ^3(c+d x)}{a+i a \tan (c+d x)} \, dx &=\frac{\cot ^2(c+d x)}{2 d (a+i a \tan (c+d x))}-\frac{\int \cot ^3(c+d x) (-4 a+3 i a \tan (c+d x)) \, dx}{2 a^2}\\ &=-\frac{\cot ^2(c+d x)}{a d}+\frac{\cot ^2(c+d x)}{2 d (a+i a \tan (c+d x))}-\frac{\int \cot ^2(c+d x) (3 i a+4 a \tan (c+d x)) \, dx}{2 a^2}\\ &=\frac{3 i \cot (c+d x)}{2 a d}-\frac{\cot ^2(c+d x)}{a d}+\frac{\cot ^2(c+d x)}{2 d (a+i a \tan (c+d x))}-\frac{\int \cot (c+d x) (4 a-3 i a \tan (c+d x)) \, dx}{2 a^2}\\ &=\frac{3 i x}{2 a}+\frac{3 i \cot (c+d x)}{2 a d}-\frac{\cot ^2(c+d x)}{a d}+\frac{\cot ^2(c+d x)}{2 d (a+i a \tan (c+d x))}-\frac{2 \int \cot (c+d x) \, dx}{a}\\ &=\frac{3 i x}{2 a}+\frac{3 i \cot (c+d x)}{2 a d}-\frac{\cot ^2(c+d x)}{a d}-\frac{2 \log (\sin (c+d x))}{a d}+\frac{\cot ^2(c+d x)}{2 d (a+i a \tan (c+d x))}\\ \end{align*}
Mathematica [B] time = 0.834068, size = 414, normalized size = 4.6 \[ \frac{\csc \left (\frac{c}{2}\right ) \sec \left (\frac{c}{2}\right ) \csc ^2(c+d x) \sec (c+d x) \left (-2 d x \sin (2 c+d x)+i \sin (2 c+d x)-2 d x \sin (2 c+3 d x)+9 i \sin (2 c+3 d x)+2 d x \sin (4 c+3 d x)-i \sin (4 c+3 d x)+6 i d x \cos (2 c+d x)-3 \cos (2 c+d x)+2 i d x \cos (2 c+3 d x)+7 \cos (2 c+3 d x)-2 i d x \cos (4 c+3 d x)+\cos (4 c+3 d x)-4 i \sin (d x) \log \left (\sin ^2(c+d x)\right )+4 i \sin (2 c+d x) \log \left (\sin ^2(c+d x)\right )+4 i \sin (2 c+3 d x) \log \left (\sin ^2(c+d x)\right )-4 i \sin (4 c+3 d x) \log \left (\sin ^2(c+d x)\right )+\cos (d x) \left (-12 \log \left (\sin ^2(c+d x)\right )-6 i d x-5\right )+12 \cos (2 c+d x) \log \left (\sin ^2(c+d x)\right )+4 \cos (2 c+3 d x) \log \left (\sin ^2(c+d x)\right )-4 \cos (4 c+3 d x) \log \left (\sin ^2(c+d x)\right )+64 \sin (c) \tan ^{-1}(\tan (d x)) \sin ^2(c+d x) (\cos (c+d x)+i \sin (c+d x))+2 d x \sin (d x)-25 i \sin (d x)\right )}{64 a d (\tan (c+d x)-i)} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.075, size = 106, normalized size = 1.2 \begin{align*}{\frac{{\frac{i}{2}}}{ad \left ( \tan \left ( dx+c \right ) -i \right ) }}+{\frac{7\,\ln \left ( \tan \left ( dx+c \right ) -i \right ) }{4\,ad}}+{\frac{\ln \left ( \tan \left ( dx+c \right ) +i \right ) }{4\,ad}}-{\frac{1}{2\,ad \left ( \tan \left ( dx+c \right ) \right ) ^{2}}}+{\frac{i}{ad\tan \left ( dx+c \right ) }}-2\,{\frac{\ln \left ( \tan \left ( dx+c \right ) \right ) }{ad}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.29105, size = 402, normalized size = 4.47 \begin{align*} \frac{14 i \, d x e^{\left (6 i \, d x + 6 i \, c\right )} +{\left (-28 i \, d x - 1\right )} e^{\left (4 i \, d x + 4 i \, c\right )} - 2 \,{\left (-7 i \, d x - 5\right )} e^{\left (2 i \, d x + 2 i \, c\right )} - 8 \,{\left (e^{\left (6 i \, d x + 6 i \, c\right )} - 2 \, e^{\left (4 i \, d x + 4 i \, c\right )} + e^{\left (2 i \, d x + 2 i \, c\right )}\right )} \log \left (e^{\left (2 i \, d x + 2 i \, c\right )} - 1\right ) - 1}{4 \,{\left (a d e^{\left (6 i \, d x + 6 i \, c\right )} - 2 \, a d e^{\left (4 i \, d x + 4 i \, c\right )} + a d e^{\left (2 i \, d x + 2 i \, c\right )}\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 2.99365, size = 141, normalized size = 1.57 \begin{align*} \begin{cases} - \frac{e^{- 2 i c} e^{- 2 i d x}}{4 a d} & \text{for}\: 4 a d e^{2 i c} \neq 0 \\x \left (\frac{\left (7 i e^{2 i c} + i\right ) e^{- 2 i c}}{2 a} - \frac{7 i}{2 a}\right ) & \text{otherwise} \end{cases} + \frac{7 i x}{2 a} - \frac{2 \log{\left (e^{2 i d x} - e^{- 2 i c} \right )}}{a d} + \frac{2 e^{- 4 i c}}{a d \left (e^{4 i d x} - 2 e^{- 2 i c} e^{2 i d x} + e^{- 4 i c}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.38539, size = 143, normalized size = 1.59 \begin{align*} \frac{\frac{\log \left (\tan \left (d x + c\right ) + i\right )}{a} + \frac{7 \, \log \left (i \, \tan \left (d x + c\right ) + 1\right )}{a} - \frac{8 \, \log \left ({\left | \tan \left (d x + c\right ) \right |}\right )}{a} - \frac{7 \, \tan \left (d x + c\right ) - 9 i}{a{\left (\tan \left (d x + c\right ) - i\right )}} + \frac{2 \,{\left (6 \, \tan \left (d x + c\right )^{2} + 2 i \, \tan \left (d x + c\right ) - 1\right )}}{a \tan \left (d x + c\right )^{2}}}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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